Announcement

Collapse
No announcement yet.

Linear Programming - ETEA Model Test MCQS - Part - VI

Collapse
X
 
  • Filter
  • Time
  • Show
Clear All
new posts

  • Linear Programming - ETEA Model Test MCQS - Part - VI

    In a test of Mathematics, there are two types of questions to be answered?short answered and long answered. The relevant data is given below
    0
    $5x+10y\le 180$ , $x\le 10,\ y\le 14$
    0%
    0
    $x+10y\ge 180$ , $x\le 10,\ y\le 14$
    0%
    0
    $5x+10y\ge 180$ , $x\ge 10,\ y\ge 14$
    0%
    0
    $5x+10y\le 180$ , $x\ge 10,\ y\ge 14$
    0%
    0

  • #2
    The objective function for the above question is
    0
    $10x+14y$
    0%
    0
    $5x+10y$
    0%
    0
    $3x+5y$
    0%
    0
    $5y+3x$
    0%
    0

    Comment


    • #3
      The vertices of a feasible region of the above question are
      0
      (0, 18), (36, 0)
      0%
      0
      (0, 18), (10, 13)
      0%
      0
      (10, 13), (8, 14)
      0%
      0
      (10, 13), (8, 14), (12, 12)
      0%
      0

      Comment


      • #4
        The maximum value of objective function in the above question is
        0
        100
        0%
        0
        92
        0%
        0
        95
        0%
        0
        94
        0%
        0

        Comment


        • #5
          A factory produces two products A and B. In the manufacturing of product A, the machine and the carpenter requires 3 hour each and in manufacturing of product B, the machine and carpenter requires 5 hour and 3 hour respectively. The machine and carpenter work at most 80 hour and 50 hour per week respectively. The profit on A and B is Rs. 6 and 8 respectively. If profit is maximum by manufacturing x and y units of A and B type product respectively, then for the function $6x+8y$ the constraints are
          0
          $x\ge 0,\ y\ge 0,\ 5x+3y\le 80,\ 3x+2y\le 50$
          0%
          0
          $x\ge 0,\ y\ge 0,\ 3x+5y\le 80,\ 3x+3y\le 50$
          0%
          0
          $x\ge 0,\ y\ge 0,\ 3x+5y\ge 80,\ 2x+3y\ge 50$
          0%
          0
          $x\ge 0,\ y\ge 0,\ 5x+3y\ge 80,\ 3x+2y\ge 50$
          0%
          0

          Comment


          • #6
            A shopkeeper wants to purchase two articles A and B of cost price Rs. 4 and 3 respectively. He thought that he may earn 30 paise by selling article A and 10 paise by selling article B. He has not to purchase total article worth more than Rs. 24. If he purchases the number of articles of A and B, x and y respectively, then linear constraints are
            0
            $x\ge 0,\ y\ge 0,\ 4x+3y\le 24$
            0%
            0
            $x\ge 0,\ y\ge 0,\ 30x+10y\le 24$
            0%
            0
            $x\ge 0,\ y\ge 0,\ 4x+3y\ge 24$
            0%
            0
            $x\ge 0,\ y\ge 0,\ 30x+40y\ge 24$
            0%
            0

            Comment


            • #7
              In the above question the is o-profit line is
              0
              $3x+y=30$
              0%
              0
              $x+3y=20$
              0%
              0
              $3x-y=20$
              0%
              0
              $4x+3y=24$
              0%
              0

              Comment


              • #8
                The sum of two positive integers is at most 5. The difference between two times of second number and first number is at most 4. If the first number is x and second number y, then for maximizing the product of these two numbers, the mathematical formulation is
                0
                $x+y\ge 5$ , $2y-x\ge 4,\ \ x\ge 0,\ y\ge 0$
                0%
                0
                $x+y\ge 5$ , $-2x+y\ge 4,\ \ x\ge 0,\ y\ge 0$
                0%
                0
                $x+y\le 5$ , $2y-x\le 4,\ \ x\ge 0,\ y\ge 0$
                0%
                0
                None of these
                0%
                0

                Comment


                • #9
                  For the L.P. problem Max $z=3{{x}_{1}}+2{{x}_{2}}$ such that $2{{x}_{1}}-{{x}_{2}}\ge 2$ , ${{x}_{1}}+2{{x}_{2}}\le 8$ and ${{x}_{1}},\ {{x}_{2}}\ge 0$ , $z=$
                  0
                  12
                  0%
                  0
                  24
                  0%
                  0
                  36
                  0%
                  0
                  40
                  0%
                  0

                  Comment


                  • #10
                    For the L.P. problem Min $z=-{{x}_{1}}+2{{x}_{2}}$ such that $-{{x}_{1}}+3{{x}_{2}}\le 0,$ ${{x}_{1}}+{{x}_{2}}\le 6,\ {{x}_{1}}-{{x}_{2}}\le 2$ and ${{x}_{1}},\ {{x}_{2}}\ge 0$ , ${{x}_{1}}=$
                    0
                    2
                    0%
                    0
                    8
                    0%
                    0
                    10
                    0%
                    0
                    12
                    0%
                    0

                    Comment

                    Working...
                    X